300 ml of O₂ diffused through a porous pot in 50 sec. How long it will take 500 ml of CO₂ to diffuse under similar conditions.

According to Graham's law the rate of diffusion is inversely proportional to square root of its molecular weight

$\frac{r_{\mathrm{O}_{2}}}{r_{\mathrm{CO}_{2}}=\sqrt{\frac{M_{\mathrm{O_{2}}}{M_{\mathrm{C

O}_{2}}}}$

Rate of diffusion of oxygen is

$\frac{300}{50}=6$

Rate of diffusion of carbon dioxide is

$\frac{500}{\mathrm{t}}$

$\sqrt{\frac{44}{32}}$

$\frac{6}{\frac{500}{t}}=\sqrt{\frac{44}{32}}$

$t=\frac{500}{6}\sqrt{\frac{44}{32}}$

$t=\frac{500}{6}\sqrt{\frac{11}{8}}$

t=97.72 sec