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300ml of cold dry and pure oxygen is subjected to silent electric discharge. 10% of it converted to ozone. Volume of ozonized oxygen is

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310ml

270ml

290ml

280 ml

answer is C.

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Detailed Solution

$\begin{array}{l} 3 V 2 V \\ 3 O_{2} (g) ⇌ 2 O_{3} (g) \\ (300 - 30) 20 \end{array}$
Volume of ozonized oxygen = (270+20) = 290ml

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