3.15 grams of solute is present in 200ml of 0.25 M solution. The solute may be

What is the maximum resistance which can be made using three resistors each of resistance 1/3&nbsp;Ω?

Two resistances <math><mrow><msub><mtext>R</mtext><mtext>1</mtext></msub><mtext> </mtext><mtext>and</mtext><mtext> </mtext><msub><mtext>R</mtext><mtext>2</mtext></msub><mrow><mo>(</mo><mrow><msub><mtext>R</mtext><mtext>1</mtext></msub><mo>&lt;</mo><msub><mtext>R</mtext><mtext>2</mtext></msub></mrow><mo>)</mo></mrow></mrow></math><xml> </xml> are connected in parallel the equivalent resistance of the system (R) is such that

A uniform wire of resistance <math><mrow><mtext>50</mtext><mtext> </mtext><mi>Ω</mi></mrow></math><xml> </xml> is cut into five equal parts. These parts are now connected in parallel. Then the equivalent resistance of the combination is

A piece of wire of resistance&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><mi mathvariant="normal">R</mi></math>&nbsp;is cut into five equal parts. These parts are then connected in parallel. If the equivalent resistance of this combination is&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><msup><mi mathvariant="normal">R</mi><mo>'</mo></msup></math>, then the ratio&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac bevelled="true"><mi mathvariant="normal">R</mi><msup><mi mathvariant="normal">R</mi><mo>'</mo></msup></mfrac></math>&nbsp;is _______________.

A bulb is connected to a cell. How is the resistance of the circuit affected if another identical bulb is connected in parallel?

3.15 grams of solute is present in 200ml of 0.25 M solution. The solute may be

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material