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3.15 grams of solute is present in 200ml of 0.25 M solution. The solute may be
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Correct option is D
Molarity of a solution is defined as the amount of solute dissolved in 1L of solution.
M = 0.25 M, grams of solute = 3.15 g ,vol. of solution = 200 mL = 0.2 L
So, ; molecular mass = 63 g/mol
H2C2O4 = 90 g/mol ;HCl = 36.5 g/mol ; H2SO4 = 98 g/mol ; HNO3 = 63 g/mol
Hence, correct option is: (D)
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