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3.2 mole of hydrogen iodide were heated in a sealed bulb at 444°C till the equilibrium was reached. The degree of dissociation of HI at this temperature was found to be 22%. The number of moles of hydrogen iodide present at equilibrium are:

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4.00

2.496

2.00

1.87

answer is A.

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Detailed Solution

$\underset{a (1 - x)}{\underset{a}{2 HI}} ⇌ \underset{ax / 2}{\underset{0}{H_{2}}} + \underset{ax / 2}{\underset{0}{I_{2}}}$
Given, $x = \frac{22}{100}$
and a = 3.2
$∴ [HI] at eq . = 3 .2 \times (1 - \frac{22}{100}) = 2 .496$

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