[(3/2)/(1/2)×(3/2)]/[(3/2)×(1/2)/(3/2)]=

[(3/2)/(1/2)×(3/2)]/[(3/2)×(1/2)/(3/2)]==[(3/2)×(2/1)×(3/2)]/[(3/2)×(1/2)×(2/3)]=(9/2)/(1/2)=(9/2)×(2/1)=9

[(3/2)/(1/2)×(3/2)]/[(3/2)×(1/2)/(3/2)]==[(3/2)×(2/1)×(3/2)]/[(3/2)×(1/2)×(2/3)]=(9/2)/(1/2)=(9/2)×(2/1)=9

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$[(3 / 2) / (1 / 2) \times (3 / 2)] / [(3 / 2) \times (1 / 2) / (3 / 2)] =$

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$[(3 / 2) / (1 / 2) \times (3 / 2)] / [(3 / 2) \times (1 / 2) / (3 / 2)] =$

$= [(3 / 2) \times (2 / 1) \times (3 / 2)] / [(3 / 2) \times (1 / 2) \times (2 / 3)]$

$= (9 / 2) / (1 / 2)$

$= (9 / 2) \times (2 / 1) = 9$

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