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Q.

3/4 th of first order reaction was completed in 32min, 15/16 the part will be completed in

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a

16 min

b

64 min

c

32 min

d

24 min

answer is B.

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Detailed Solution

detailed_solution_thumbnail

$2 t_{50 %} = t_{75 %} = 32 \min$

$t_{50 %} = 16 \min$

$\frac{15}{16}$ part will be completed in 4t_50%

Time required = 4 $\times$ 16 = 64 mins

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