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35 mL sample of hydrogen peroxide gives of 494 mL of 02 at 27° C and 1 atm pressure. Volume strength of $H_{2} O_{2}$ sample will be;

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12 V

10 V

13 V

11 V

answer is B.

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Detailed Solution

$\begin{array}{l} \frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}} \\ T_{2} = \frac{V_{1} \times T_{2}}{T_{1}} \\ T_{2} = \frac{500 \times 273}{300} = 455 ml \end{array}$

$∴ 1000 ml can produce = \frac{1000 \times 455}{35}$

$= 13000 ml = 13 L .$

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