$36 g$ of glucose (molar mass $= 180 g/mol)$ is present in $500g$ of water, the molarity of the solution is

Molarity $=\frac{w\times 1000}{M\times V}$

Where $V =$ volume of water $= 500 ml$

$w=$ mass of glucose $=36g$

$M=$mol. mass of glucose $=180 g$

Molarity $=\frac{36\times 1000}{180\times 500}=0.4M$