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Q.

3.92 g. of Mohr salt (mol.wt=392) is present in 100 ml of an aqueous solution. The sulphate  ion concentration of the resulting solution is

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a

1M

b

0.2M

c

2M

d

0.02M

answer is C.

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Detailed Solution

NH42SO4FeSO46H2O→FeSO4+NH42SO4

M=WGMW×1000Vml

M=3.92392×1000100

M=3.92×10392=0.1

For sulphate ion concentration

=0.1×2=0.2M

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