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$3 \cdot C_{0} + 7 \cdot C_{1} + 11 \cdot C_{2} + \dots + (4 n + 3) \cdot C_{n} =$

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$(3 n + 2) 2^{n}$

$(2 n + 3) 3^{n}$

$(2 n + 3) 2^{n}$

$(3 n + 2) 3^{n}$

answer is C.

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Detailed Solution

$Sum = (4 n + 3 + 3) 2^{n - 1} = (2 n + 3) 2^{n}$

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