3Cl2+6NaOH→5NaCl+NaClO3+3H2O, chlorine gets

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$3 {Cl}_{2} + 6 NaOH \to 5 NaCl + {NaClO}_{3} + 3 H_{2} O$ , chlorine gets

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Both A and B

Oxidized

None

Reduced

answer is C.

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Detailed Solution

From ${Cl}_{2} \to NaCl$ , chlorine's oxidation number changes from $0 ({C l}_{2})$ to $- 1 (NaCl)$ i.e., it gets reduced. Whereas, from ${Cl}_{2} \to {NaClO}_{3}$ chlorine gets oxidized. The oxidation number changes from $0 ({Cl}_{2})$ to $+ 1 ({NaClO}_{3})$ . Hence, chlorine gets oxidized as well as reduced in the given reaction.