$3\mathrm{Cu}+8{\mathrm{HNO}}_3\to 3\mathrm{Cu}{\left({\mathrm{NO}}_3\right)}_2+2\mathrm{NO}+4{\mathrm{H}}_2\mathrm{O}$.
In above reaction equivalent mass of HNO₃ is (M. wt. x) value of 3x is equal to___________.
 

$$\begin{gathered} 3\mathrm{Cu}+8{\mathrm{HNO}}_3\to 2NO+3\mathrm{Cu}{\left({\mathrm{NO}}_3\right)}_2+4{\mathrm{H}}_2\mathrm{O} \\ 8{\mathrm{HNO}}_3\to 2\mathrm{NO} \end{gathered}$$
1 molecule${\mathrm{HNO}}_3 \to \frac{2}{8}=1/4$
$\text{nF=}\frac{1}{4}\times 3$
$\mathrm{Eq}.{\mathrm{HNO}}_3 ?=\frac{\mathrm{M}.\mathrm{wt}}{\mathrm{nf}}$
$\mathrm{M}.\mathrm{wt}.\mathrm{x}=\frac{\mathrm{M}.\mathrm{wt}}{3}\times 4 \mathrm{x}=4/3$
The value of 3 x 
$=3\times \frac{4}{3}=4$