3g of activated charcoal was added to 50ml of the acetic acid solution (0.06N) in a flask. After an hour, it was filtered and the strength of the filtrate was found to be 0.042N. The amount of acetic acid adsorbed (per gram of charcoal ) is:

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3g of activated charcoal was added to 50ml of the acetic acid solution (0.06N) in a flask. After an hour, it was filtered and the strength of the filtrate was found to be 0.042N. The amount of acetic acid adsorbed (per gram of charcoal ) is:

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18 mg

36 mg

42 mg

54 mg

answer is A.

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Detailed Solution

Change in molarity when $C H_{3} C O O H$ gets adsorbed = 0.06 – 0.042 = 0.018

Number of millimoles of $C H_{3} C O O H$ adsorbed = $0.018 \times 50 = 0.90$ mmol

Mass adsorbed $0.90 \times 60 = 54$ mg ( $∵$ Molar mass of $C H_{3} C O O H = 60 g / m o l$ )

Mass adsorbed per gram = $\frac{54}{3}$ = 18 mg = 0.018 g

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