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$3 {HNO}_{2} \to {HNO}_{3} + H_{2} O + 2 NO$ is a dispraportionation reaction. EW of HNO₂ is

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M/3

3M/2

2M/3

answer is C.

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Detailed Solution

$H \overset{+ 3}{N} O_{2} \to H \overset{+ 5}{N} O_{3} + \overset{+ 2}{N} O$

OHR; $H \overset{+ 3}{N} O_{2} \to H \overset{+ 5}{N} O_{3}$

Increase in oxidation states=2

EW of HNO₂as reductant =M/2

RHR; $H \overset{+ 3}{N} O_{2} \to \overset{+ 2}{NO}$

Decrease in oxidation states =1

EW of HNO₂as oxidant=M/1

$EW of {HNO}_{2} in the reaction = \frac{M}{2} + \frac{M}{1} = \frac{3 M}{2}$

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