3L Mixture of propane and butane on complete combustion at 298K and 1atm gave 10L CO₂. Calculate the composition of gas mixture

$$\begin{gathered} {\mathrm{C}}_3{\mathrm{H}}_8+5{\mathrm{O}}_2\to 3{\mathrm{CO}}_2+4{\mathrm{H}}_2\mathrm{O},\mathrm{ratio} \mathrm{of} \mathrm{volumes} \mathrm{of} \mathrm{propane} \mathrm{and} {\mathrm{CO}}_2=1:3 \\ {\mathrm{C}}_4{\mathrm{H}}_{10}+\frac{13}{2}{\mathrm{O}}_2\to 4{\mathrm{CO}}_2+5{\mathrm{H}}_2\mathrm{O},\mathrm{ratio} \mathrm{of} \mathrm{vol}. \mathrm{of} \mathrm{butane} \mathrm{and} {\mathrm{CO}}_2=1:4 \end{gathered}$$From options, option(B) is suitable.

$\because$ 2L C₃H₈ gave 6L and 1L C₄H₁₀ gave 4L of CO₂ (totally 10L)