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Q.

4.9 mg of $H_{2} {SO}_{4}$ Is present in 1L of an aqueous solution. The $p^{H}$ Of the solution is

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a

$3.7$

b

$5$

c

$4.3$

d

$4$

answer is A.

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Detailed Solution

$N = |H^{+}| = \frac{4.9 \times 10^{- 3}}{49} \times \frac{1}{1} = 10^{- 4}$

$∴ p^{H} = 4$

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