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4-amino-3-methylbutanoic acid is treated with thionyl chloride followed by ammonia to obtain compound $X . X$ on reaction with, bromine in an ankaline medium gave compound Y. For estimation, was titrated with perchloric acid. The volume of 0.1 M perchloric acid needed to react with 0.22 g of Y is:

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200 mL

80 mL

120 mL

50 mL

answer is A.

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Detailed Solution

$Y + 2 {HClO}_{4} \to Salt$

No. of moles of ${HClO}_{4}$ needed = $\frac{0.22 \times 2}{88} = \frac{1}{200}$

$\frac{1}{200} = 0.1 \times V_{L}$

$V_{L} = \frac{1}{20} = 0.05 L = 50 ml$

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