4–bromophenylacetic acid is obtained by which of the following series of reactions?

$Benzene\underset{\begin{array}{l}2)Mg/ether\\ 3)C{H}_{3}COO{C}_2{H}_5\end{array}}{\overset{1)B{r}_2/FeB{r}_3}{\to }}\left(Oneequivalent\right)$

$Benzene\underset{\begin{array}{l}2)B{r}_2/FeB{r}_3\\ 3)Zn-Hg/HC\mathcal{l}\\ 4)C{\mathcal{l}}_2,\Delta \\ 5)H_{2}O/O{H}^{-}\end{array}}{\overset{1)C{H}_3,COC\mathcal{l}\left(A\mathcal{l}C{\mathcal{l}}_3\right)}{\to }}$

$P-BromoToulene\underset{\begin{array}{l}2)C{N}^{-}\\ 3)H_{2}O,H^{+}\end{array}}{\overset{1)B{r}_2,hv\left(1eq\right)}{\to }}$

$1-Bromo-4-ethylbenzene\underset{\begin{array}{l}2)C{N}^{-}\\ 3)H_{2}O/H^{+}\\ 4)\Delta \end{array}}{\overset{1)B{r}_2,hv\left(1eq\right)}{\to }}$