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Q.

4 g of a mixture of Na2CO3 and NaHCO3 on heating liberates 448 ml of CO2 at STP. Percentage of Na2CO3 in the mixture is

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answer is 16.

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Detailed Solution

Only NaHCO3 undergo decomposition
2NaHCO3Na2CO3+H2O+CO2 168 g                          22,400 ml
22400ml CO2 obtained from 168 g
448 ml CO2 produced from 
WNaHCO3=448×16822.400=3.36gWNaHCO3=43.36=0.64g%Na2CO3=0.644×100=16

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