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4 gm of He at 27°C is mixed with 16 gm of O₂ at 37°C. If both gases are considered as ideal gases, temperature of the mixture will be nearly:

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34°C

29°C

31.5°C

32.6°C

answer is C.

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Detailed Solution

Let temperature of mixture be T then
$n_{1} C_{V_{1}} (T - T_{1}) = n_{2} C_{V_{2}} (T_{2} - T) \Rightarrow T = \frac{n_{1} C_{V_{1}} T_{1} + n_{2} C_{V_{2}} T_{2}}{n_{1} C_{V_{1}} + n_{2} C_{V_{2}}} = 31^{o} C$

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