4 grams of an ideal gas occupy 5.6035 litres of volume at 546 K and 2 atm, pressure. What is its molecular weight?

Ideal gas equation

Detailed explanation:

According to ideal gas equation

 PV = nRT

As we know n=w/M

Then

$\mathrm{PV}=\frac{\mathrm{W}}{\mathrm{M}}\mathrm{RT}$

$\mathrm{M}=\frac{\mathrm{W}}{\mathrm{PV}}\mathrm{RT}$

R=0.0821

$\mathrm{M}=\frac{4}{2\times 5.6035}0.0821\times 546$

M=16

Hence the required option is B