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4 grams of H₂(g) at anode and 32 grams of O₂(g) at cathode undergo combustion in a fuel cell. Number of Faradays produced during this process if the fuel cell efficiency is 70% is

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1.4F

5.6 F

2.8 F

4.2 F

answer is C.

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Detailed Solution

$2 H_{2} + O_{2} \overset{4 F}{\to} 2 H_{2} O$

$∴$ Electricity produced = $4 F (\frac{70}{100})$

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