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4 grams of radioactive substance A left 1/2 gm after some time. 1 gram of another radioactive substance B left 1/4 gm in the same period. If half life of B is 2 hours, the half life of A is (in hours)

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1/4

3/4

1/2

4/3

answer is B.

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Detailed Solution

$W = \frac{W_{0}}{2^{n}}; no fo halflives n = \frac{t}{t_{1 / 2}}$

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