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Q.

4 L of 0.02 M aqueous solution of NaCl was diluted by adding one litre of water. The molality of the resultant solution is :

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a

0.012

b

0.008

c

0.004

d

0.016

answer is D.

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Detailed Solution

We know that,

M1V1=M2V2

Given: M1=0.02M,V1=4L,M2=?,V2=5L

Therefore 0.02×4L=M2×5L
M2=0.085=0.016M

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