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4 mole of PCl₅ and 2 mole of Cl₂ are heated in a 2L vessel to establish an equilibrium $[{PCl}_{5} (g) ⇌ {PCl}_{3} (g) + {Cl}_{2} (g)] .$ Equilibrium molar concentration of PCl₃ is 1. Then the value of K_c for the above equilibrium is

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a

1 mole / L

b

1/3 mole / L

c

1/6 mole / L

d

2 mole / L

answer is D.

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Detailed Solution

$\begin{array}{l} {PCl}_{5} (g) ⇌ {PCl}_{3} (g) + {Cl}_{2} (g) \\ \frac{4 - x}{2} \frac{x}{2} \frac{x + 2}{2} \\ as \frac{x}{2} = 1 ∴ x = 2 \\ \frac{4 - 2}{2} \frac{2}{2} \frac{4}{2} \\ ∴ 1 1 2 \\ ∴ k_{c} = \frac{1 \times 2}{1} = 2 mole / L \end{array}$

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