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Q.

40 Calorie of heat is needed to raise the temperature of 1 mole of an ideal monoatomic gas from 200C to 300C at a constant pressure. The amount of heat required to raise its temperature over the same interval at a constant volume.

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a

20 Cal

b

40 Cal

c

60 Cal

d

80 Cal

answer is A.

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Detailed Solution

given heat required raise the temperature of gas Qp=40 calorie; number of mole μ=1; change in temperature dT=100C Qp=μCPdT ; here CP=specific heat at constant pressure Qp=1xCpx(30-20)=40calorie Cp = 4 Cal/mol-K we know Cv - Cp = R; here  Cv=specific heat at constant volume; R=Universal gas constant=2cal/mol-K Cv = Cp  R = 4  2 = 2 Cal/mol-K heat required raise the temperature of gas Qv = µCvdT = 1 x 2 x (30-20) = 20 cal

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