4.0 g of NaOH is dissolved in 100 cc of solution. The normality of the solution is

As per given data,

Weight. of NaOH, w$=4.0g$

$\text{GEW of NaOH}=\frac{\text{GMW}}{\text{Acidity}}=\frac{40}{1}=40g$

Volume of solution ,V$=100\text{ mL}$

From the formula of normality,

    $N=\frac{w}{GEW}\times \frac{1000}{\text{V}\text{in mL}}$

      $=\frac{4.0}{40}\times \frac{1000}{100}$

      $=1.0\text{N}$

Therefore, the normality of the given solution is 1.0N.