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Q.

40 ml of 0.5 M aqueous solution of oxalic acid (molar mass=126) is shaken with 25.2 g of wood charcoal. The final concentration of the solution after adsorption of oxalic acid is 0.25M. If the weight of oxalic acid [in gram] adsorbed per gram of carbon is represented as $y \times 10^{- 2}$ then find the value of y. (Assume volume of oxalic acid remains constant)

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answer is 5.

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Detailed Solution

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Millimoles of oxalic acid absorbed
$= 40 \times 0.5 - 0.25 \times 40 = 10$
$∴$ Number of moles of oxalic acid $= 10 \times 10^{- 3}$
Amount of oxalic acid $= 10 \times 10^{- 3} \times 126 g$
$= 1.26 g$
$∴$ Amount of oxalic acid adsorbed by per gram of charcoal
$= \frac{1.26}{25.2} = 5 \times 10^{- 2} = 0.05$

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