40% (w/w) sulphuric acid of specific gravity 1.47 g/cc is present in a 1litre lead storage battery. Due to discharge after certain time 20% (w/w) sulphuric acid of specific gravity 0.98g/CC was left. Quantity of electricity produced by it is

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6 F

12 F

4 F

8 F

answer is B.

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Detailed Solution

In lead storage battery for H₂SO₄ equivalent weight and molecular weight is same as n-factor is 1. Molarity and Normality is equal

Decrease in molarity = $\frac{10}{98} (40 \times 1.47 - 20 \times 0.98) = \frac{392}{98} = 4$

Number of equivalents = mumber of faradays = 4

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