40.0 g of a solute is dissolved in 500 mL of a solvent ,to give a solution with a volume of 515 m.L. The solvent has a density of 1.00 g/mL. Which statement about this solution is correct?

Molarity of solvant in 500 mL
= 500 g
let molar mass of soluble = M

$\text{ molality }=\frac{(40/m)}{\left(\frac{500}{1000}\right)}=\frac{40}{m}\times 2=\frac{80}{m}$

$\text{ Molaritge }=\frac{(40/M)}{\left(\frac{515}{1000}\right)}=\frac{40}{\mathrm{m}}\times \frac{1000}{515}$

$=\frac{776}{m}$

$\frac{80}{\mathrm{m}}>\frac{77.6}{M}$

Molarity $>$Molarity

Hence , 

40.0 g of a solute is dissolved in 500 mL of a solvent ,to give a solution with a volume of 515 m.L. The solvent has a density of 1.00 g/mL.  The statement about this solution The molarity is lower than the molality is correct.