Q.

4.5 g of compound A (MW = 90) was used to make 250 mL of its aqueous solution. The molarity of the solution in M is x × 10–1. The value of x is ____.
(Rounded off to the nearest integer)

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answer is 2.

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Detailed Solution

Molarity = No moles of solute  Volume of solution(L) =4.5/90250×10-3=0.2=2×10-1M

So correct value of x=2.

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4.5 g of compound A (MW = 90) was used to make 250 mL of its aqueous solution. The molarity of the solution in M is x × 10–1. The value of x is ____.(Rounded off to the nearest integer)