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Q.

45 g of ethylene glycol $(C_{2} H_{6} O_{2})$ is mixed with 600 g of water. The freezing point of the solution is ( $K_{f}$ for water is $1.86 K . {kgmol}^{- 1}$ )

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a

270.95 K

b

373.95 K

c

370.95 K

d

273.95 K

answer is B.

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Detailed Solution

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$Δ T_{f} = K_{f} m = K_{f} \frac{W_{2}}{M_{2}} \times \frac{1000}{W_{1}}$

$= 1.86 \times \frac{45}{62} \times \frac{1000}{600}$ $= 2.25 K$

$T_{f} = 273.15 - 2.25 = 270.95 K$

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