$4\mathrm{d},5\mathrm{p},5\mathrm{f}\text{ and }6\mathrm{p}$ orbitals are arranged in the order of decreasing energy. The correct option is

Higher the value of (n+l) for an orbital, higher is its energy. However, if two different types of orbitals have same value of (n+l) the orbital with lower value of n has lower energy. Therefore, decreasing order of energy of the given orbitals is $5 \mathrm{f}\left(5+3\right)>6 \mathrm{p}\left(6+1\right)>5 \mathrm{p}\left(5+1\right)>4 \mathrm{d}\left(4+2\right).$