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4g of Substance A, dissolved in 100g H₂O depressed the freezing point of water by 0.1°C. While 4g of another substance B, depressed the f.pt by 0.2°C. What is the relation between molecular weights of A and B.

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M_A = M_B

M_A = 4M_B

M_A = 2M_B

M_A = 0.5 M_B

answer is D.

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Detailed Solution

$\begin{array}{l} \frac{{({ΔT}_{f})}_{A}}{{({ΔT}_{f})}_{B}} = \frac{m_{A}}{m_{B}} = \frac{W_{A}}{M_{A}} \times \frac{M_{B}}{W_{B}} \\ \frac{0 .1}{0 .2} = \frac{4}{M_{A}} \times \frac{M_{B}}{4} \Rightarrow M_{A} = 2 M_{B} \end{array}$

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