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4g of Substance A dissolved in 100g H₂O depressed the freezing point of water by 0.1°C, while 4g of another substance B dissolved in 100g of water depressed the freezing point by 0.2°C. What is the relation between molecular weights of A and B.

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M_A = M_B

M_A = 4M_B

M_A = 2M_B

M_A = 0.5 M_B

answer is D.

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Detailed Solution

$\begin{array}{l} {ΔT}_{f} = K_{f} m \Rightarrow 0 .1 = K_{f} \times \frac{4}{M_{A}} \times \frac{1000}{100} \\ \frac{0 .2 \times M_{B}}{40} = \frac{0 .1 \times M_{A}}{40} \\ \Rightarrow M_{A} = 2 M_{B} \end{array}$

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