$4 HCl + O_{2} \overset{(X)}{⟶} 2 {Cl}_{2} + 2 H_{2} O . X is$

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${MnO}_{2}$

${Fe}_{2} O_{3}$

$V_{2} O_{5}$

${CuCl}_{2}$

answer is B.

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Detailed Solution

Deacon process is the preparation of chlorine gas using Hydrochloric acid gas with atmospheric oxygen (raw oxygen straight from photosynthesis) using a catalyst (cupric chloride).

4HCl + O₂ $\to$ 2H₂O + 2Cl₂

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