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Q.

4K+O2→[I];4Na+O2→[II]

I, II represents:

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a

I→4H2O,II→4Na2O

b

I→K2O,II→Na2O

c

I→2K2O,II→2Na2O

d

I→KOH,II→NaOH

answer is C.

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Detailed Solution

4K+O2→2K2O 

4Na + O2→2Na2O

Both reactions are combination reactions.

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