4NH₃ + 5O₂ $\to$ 4NO + 6H₂O. When 1 mole each of NH₃ and O₂ react with each other, the incorrect statement is

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0.8 moles of NO is formed

0.2 moles of Ammonia is excess reagent

0.05 moles of oxygen is excess reagent

1.2 mole of water is formed

answer is C.

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Detailed Solution

oxygen is limiting reagent

Moles of NO formed = $\frac{4}{5}$ = 0.8

Moles of NH₃ reacted = 0.8 mole

Excess NH₃ = 1- 0.8 = 0.2

Moles of water formed = $\frac{6}{5}$ =1.2 mole

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