5.00moles of hydrogen gas, 3 moles of white phosphorus  $\left\{P_4\left(s\right)\right\}$ and 12 moles of oxygen gas are taken in a sealed flask and allowed to reacts as follows:
$H_2\left(g\right)+P_4\left(s\right)+O_2\left(g\right)\underset{ }{\to }{H}_{3}P{O}_4$ 
Determine the number of moles of ortho-phosphoric acid that can be produced, considering that the reaction occurs in 90% yield.