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Q.

5.3 grams of  Na2CO3 is dissolved  in 200ml of a solution. It is diluted by adding 800 ml of water. 100ml of the resulting solution requires ‘V’ ml of 0.02N H2SO4 solution for complete neutralization. ‘V’ is

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a

250 ml

b

100ml

c

500ml

d

2000ml

answer is C.

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Detailed Solution

i)   N=5.353×1000200
     N = 0.5N
ii)  V1N1=V2N2
    2000.5 = 200+800N2
    N2=0.1N
iii) VbNb=VaNa
    1000.1=Va0.02
     Va=500ml

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