5.3g of sodium carbonate and 6g of ethanoic acid react with each other and form 2.2g of carbon dioxide, 0.9g of water, and form sodium ethanoate. Find the weight of the sodium ethanoate?

5.3g of sodium carbonate and 6g of ethanoic acid react with each other and form 2.2g of carbon dioxide, 0.9g of water, and form sodium ethanoate.
Given,
Mass of sodium carbonate = 5.3g
Mass of ethanoic acid = 6g
Mass of carbon dioxide = 2.2g
Mass of water= 0.9g
The sum of Mass of reactant = sum of Mass of product
$\Rightarrow 5.3g+6g=2.2+0.9g+x$
$\Rightarrow 11.3g=3.1g+x$
$\Rightarrow x=11.3-3.1$
$\Rightarrow x=8.2g$