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5 cards and 5 envelopes are numbered 1,2,3,4,5 and cards are to be placed in envelopes so that each envelope contains exactly one card and no cards is placed in the envelope bearing the same number and more over the card numbered 1 is always placed in envelope numbered 2. Then number of ways is

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answer is C.

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case(i) case(ii)
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$D_{3} + D_{4} = 2 + 9 = 11$

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