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5 different marbles are placed in 5 different boxes randomly given that each box can hold any number of marbles. If p is the probability that exactly two boxes remain empty, then find the value of $[\frac{1}{p}]$ where $[.]$ represents GIF

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answer is D.

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Detailed Solution

$n (S) = 5^{5} n (A) = 5 C_{2} ((1 + 1 + 3) o r (1 + 2 + 2)) = 1500 p = \frac{1500}{55} = \frac{12}{25} [\frac{1}{p}] = 2$

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