5 g of steam at 100⁰C is mixed with 5g of ice at 0⁰C. What is the final temperature of the mixture ?

Given, mass of steam = 5g = mass of ice Temperature of steam = 100⁰C

Temperature of ic = 0⁰C

Since, latent heat of vaporisation, Lv = 540 cal/g Latent heat of fusion. L’_F = 80cla/g

Now, heat by steam to get converted into, at 100⁰C and Q₁ = m x 540 = 2700cal

 Heat needed by ice to covert itself into water at 100⁰C Q₂ = mL_F + ms$\text{Δ}$T

 = 5 x 80 + 5 x 1 x 100

  = 400 + 500 = 900

Since, Q₂ > Q₁

Temperature =100^oc