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Q.

5 J of work is required to stretch a spring through 5 cm beyond its unstretched length. The extra work required to stretch it further by an additional 5 cm shall be 

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a

5 J

b

15 J

c

25 J

d

10 J

answer is C.

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Detailed Solution

Ui=12Kx2=5 J

Uf=12k(2x)2=4[12kx2]=20 J

Work done = Uf−Ui=15 J

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