Book Online Demo
Check Your IQ

Courses

Class - 11 JEE CourseClass - 11 NEET CourseClass - 12 JEE CourseClass - 12 NEET CourseDropper JEE CourseDropper NEET CourseClass - 10 Foundation JEE CourseClass - 10 Foundation NEET CourseClass - 10 CBSE CourseClass - 9 Foundation JEE CourseClass -9 CBSE CourseClass - 8 CBSE CourseClass - 7 CBSE CourseClass - 6 CBSE Course

Q.

5 mol of N2(g)  at 5 atmospheric pressure contained in a 100L cylinder absorbed 30.26kJ of heat when it expanded to 200 L at 2 atmospheric pressure. The change in the internal energy of N2 gas is:

see full answer

Want to Fund your own JEE / NEET / Foundation preparation ??

Take the SCORE scholarship exam from home and compete for scholarships worth ₹1 crore!*
An Intiative by Sri Chaitanya

a

10kJ

b

-20.26 kJ

c

+20.26 J

d

+20.26 kJ

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

V1=100L;V2=200L;P=2 atm 

Work, W=-PV2-V1=-2atm(200-100)L=-200L atm =-200×101.30 J[∵1Latm=101.30 J]

Heat absorbed, q=30.26 kJ

 But ΔU=q+W (first law of thermodynamics) 

∴ΔU=30.26 kJ+(-20.26 kJ)=+10 kJ

 

 

Watch 3-min video & get full concept clarity
Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Books for IIT JEE
Best Books for NEET
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Books for IIT JEE
Best Books for NEET
whats app icon