Q.

5 mol of N2(g)  at 5 atmospheric pressure contained in a 100L cylinder absorbed 30.26kJ of heat when it expanded to 200 L at 2 atmospheric pressure. The change in the internal energy of N2 gas is:

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a

10kJ

b

-20.26 kJ

c

+20.26 J

d

+20.26 kJ

answer is D.

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Detailed Solution

V1=100L;V2=200L;P=2 atm 

Work, W=-PV2-V1=-2atm(200-100)L=-200L atm =-200×101.30 J[1Latm=101.30 J]

Heat absorbed, q=30.26 kJ

 But ΔU=q+W (first law of thermodynamics) 

ΔU=30.26 kJ+(-20.26 kJ)=+10 kJ

 

 

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