5 mole of an ideal gas expands isothermally and irreversibly from a pressure of 10 atm to 1 atm against a constant external pressure of 1 atm. W_irr at 300k is

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-110.83KJ

-11.224KJ

-112.2KJ

-15.921KJ

answer is B.

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Detailed Solution

$\begin{array}{l} W_{irr} = - P_{ext} (V_{2} - V_{1}) = - 1 \times (\frac{nRT}{p_{2}} - \frac{nRT}{p_{1}}) = - 1 \times (5 \times 0 .0821 \times 300) (1 - \frac{1}{10}) \\ = - 110 .8351 t - atm (1 lt - atm = 101 J) = - 11 .22 KJ \end{array}$

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