5 moles of VO and 6 moles of ${\mathrm{Fe}}_2{\mathrm{O}}_3$ are allowed to react completely according to reaction

$\mathrm{VO}+{\mathrm{Fe}}_2{\mathrm{O}}_3⟶\mathrm{FeO}+{\mathrm{V}}_2{\mathrm{O}}_5$

The number of moles of ${\mathrm{V}}_2{\mathrm{O}}_5$ formed is :

In the given reaction we have,

$\begin{array}{l}2\mathrm{VO}+\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}3{\mathrm{Fe}}_2{\mathrm{O}}_3\to 6\mathrm{FeO}+{\mathrm{V}}_2{\mathrm{O}}_5\\ 5\text{ mole }\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}6\text{ mole }\\ \hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\text{ (LR) }\end{array}$

Here, the number of moles of ${\mathrm{V}}_2{\mathrm{O}}_5$ formed is 2.