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50 g of an ideal gas is undergoing a process for which heat capacity is 50 cal/mole-K If rise in temperature during the process is 100° C then calculate work involved in process (given molar mass of gas = 10 g/mole, CP of gas = 5 R)

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29 kcal

21 kcal

-21 kcal

- 29 kcal

answer is B.

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Detailed Solution

$\begin{aligned} q = n C Δ T = 5 \times 50 \times 100 = 25 kcal \\ Δ U = n C_{v} Δ T = 5 \times 8 \times 100 = 4 kcal \end{aligned}$

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