50 gm of ${\mathrm{CaCO}}_3$ is allowed to react with 68.6 gm of ${\mathrm{H}}_3{\mathrm{PO}}_4$ then select the correct option(s): $3{\mathrm{CaCO}}_3+2{\mathrm{H}}_3{\mathrm{PO}}_4⟶{\mathrm{Ca}}_3{\left({\mathrm{PO}}_4\right)}_2+3{\mathrm{H}}_2\mathrm{O}+3{\mathrm{CO}}_2$

$$\begin{gathered} 3{\mathrm{CaCO}}_3+ 2{\mathrm{H}}_3{\mathrm{PO}}_4\to {\mathrm{Ca}}_3{\left({\mathrm{PO}}_4\right)}_2+3{\mathrm{H}}_2\mathrm{O}+3{\mathrm{CO}}_2 \\ \begin{array}{r}n=\frac{50}{100}\\ \underset{\left(\mathrm{LR}\right) }{=0.5}\end{array} \begin{array}{r}=\frac{68.6}{98}\\ 0.7\end{array} - - - \\ - \begin{array}{cc}\left[0.7-\frac{0.5}{3}\times 2\right]\times 98& \frac{0.5}{3}\times 310\\ =35.93\mathrm{g}& =51.67\mathrm{g}\end{array} 0.5 \mathrm{mole} \end{gathered}$$